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The Bitwise OR operation compares bit by bit the equal-length binary representations of the selected pair of arguments and performs the logical inclusive OR operation. The result in each position is 0 if both bits are 0; otherwise, the result is 1. The result is then transformed and given in decimal format.
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How does it work in the search window?
Select Create column in the search window toolbar, then select the Bitwise OR operation. You need to specify two arguments:
Argument | Data type |
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Number (mandatory) | integer |
Number (mandatory) | integer |
The data type of the values in the new column is integer.
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Example
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The examples in this article use values in a data table generated from the following CSV file.
If you want to try the example for yourself, download the file and upload it to your domain by clicking Data upload in the navigation panel. Name the new table After receiving the confirmation message, you can access the table from the Finder, selecting my → upload → sample → data. When you upload data from a file, all the information is included in a single column called message. To split the values and extract those we need for this operation into a new column, you can use the Split operation. Click Toggle Query Editor in the search window toolbar and paste the following LINQ query to save time:
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We want to get the Bitwise OR of the values in the posNumbers1_int and posNumbers2_int columns. To do it, we will create a new column using the Bitwise OR operation. Let's call the new column bitOR.
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Number -posNumbers1_int column
Number - posNumbers2_int column
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Click Create column and you will see the following result:
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Use the operator select... as... and add the operation syntax to create the new column. These are the valid formats of the Bitwise OR operation:
bor(integer1, integer2)integer1 | integer2
Example
You can copy the following LINQ scripts and try the above example on the my.upload.sample.data table.
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from my.upload.sample.data select split(message, ";", 17) as posNumbers1 select split(message, ";", 18) as posNumbers2 select int(posNumbers1) as posNumbers1_int select int(posNumbers2) as posNumbers2_int select bor(posNumbers1_int, posNumbers2_int) as bitOR |
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