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Description

Adds a new column that returns the cube root of the values of a given numeric field.

How does it work in the search window?

Select Create column in the search window toolbar, then select the Cube root operation. You need to specify one argument:

Argument

Data type

Number mandatory

integer, float

The data type of the values in the new column is integer or float, depending on the selected input data.

Example

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The examples in this article use values in a data table generated from the following CSV file.

View file
nameSample.data.csv

If you want to try the example for yourself, download the file and upload it to your domain by clicking Data upload in the navigation

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panel. Name the new table my.upload.sample.data and select Current date as Date parsing type. Learn more about uploading data in Uploading log files.

After receiving the confirmation message, you can access the table from the Finder, selecting my → upload → sample → data. When you upload data from a file, all the information is included in a single column called message. To split the values into different columns, you can use the Split operation. Click Toggle Query Editor in the search window toolbar and paste the following LINQ query to save time:

from my.upload.sample.data
select split(message, ";", 16) as posNumbers1,
int(posNumbers1) as posNumbers1_int

We want to get the cube root of all the values in the posNumbers1_int column. To do it, we will create a new column field using the Cube root operation. Let's call the new column field spent_cube_root.

The arguments needed to create the new column field are:

  • Number posNumbers1_int column

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Click Create columnfield and you will see the following result:

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Use the operator select... as...  and add the operation syntax to create the new column. This is the syntax for the Cube root operation:

  • cbrt(number)

Example

You can copy the following LINQ script and try the above example on the my.upload.sample.data table. 

Code Block
from my.upload.sample.data
select split(message, ";", 16) as posNumbers1,
int(posNumbers1) as posNumbers1_int
  select cbrt(posNumbers1_int) as spent_cube_root