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For example, if you add values 7 and 9 as arguments...
7 → 0111
9 → 1001
..., the result is 1110, which is converted to its corresponding decimal value (14).
7 → 0111
9 → 1001
How does it work in the search window?
Select Create column in the search window toolbar, then select the Bitwise XOR operation. You need to specify two arguments:
Argument | Data type |
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Number mandatory | integer |
Number mandatory | integer |
The data type of the values in the new column is integer.
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Example
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Rw ui textbox macro | ||
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The examples in this article use values in a data table generated from the following CSV file. |
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If you want to try the example for yourself, download the file and upload it to your domain by clicking Data upload in the navigation |
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panel. Name the new table After receiving the confirmation message, you can access the table from the Finder, selecting my → upload → sample → data. When you upload data from a file, all the information is included in a single column called message. To split the values and extract those we need for this operation into a new column, you can use the Split operation. Click Toggle Query Editor in the search window toolbar and paste the following LINQ query to save time:
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We want to get the Bitwise XOR of the values in the posNumbers1_int and posNumbers2_int columns. To do it, we will create a new column using the Bitwise XOR operation. Let's call the new column bitXOR
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Number - posNumbers1_int column
Number - posNumbers2_int column
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Click Create column and you will see the following result:
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Use the operator select
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... and add the operation syntax to create the new column. These are the valid formats of the Bitwise XOR operation:
bxor(integer1, integer2)
integer1 ^ integer2
Example
You can copy the following LINQ scripts and try the above example on the my.upload.sample.data
table.
Code Block |
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from my.upload.sample.data select split(message, ";", 17) as posNumbers1 select split(message, ";", 18) as posNumbers2 select int(posNumbers1) as posNumbers1_int select int(posNumbers2) as posNumbers2_int select bxor(posNumbers1_int, posNumbers2_int) as bitXOR |
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