ISO-3166-1 Country Name (countryname)

[ 1 Description ] [ 2 How does it work in the search window? ] [ 3 How does it work in LINQ? ]

Description

Returns the ISO-3166-1 country name from any country identification.

How does it work in the search window?

This operation needs only one argument:

Argument	Data type

Argument	Data type
Country ^mandatory	string

The data type of the new column is string.

Example

The examples in this article use values in a data table generated from the following CSV file.

If you want to try the example by yourself, download the file and upload it to your domain by clicking Data upload in the navigation pane. Name the new table my.upload.geolocation.data and select Current date as Date parsing type. Learn more about uploading data in Uploading log files.

After receiving the confirmation message, you can access the table from the finder, selecting my → upload → geolocation → data. When you upload data from a file, all the information is included in a single column called message. To split the values into different columns, you can use the Split (split) operation. Click Query code editor in the search window toolbar and paste the following LINQ query to save time:

from my.upload.geolocation.data
select split(message, ";", 5) as countryCode

We want to get the ISO-3166-1 country names corresponding to the codes in our countryCode column, so we click Create column and select the ISO-3166-1 Country Name operation. Select countryCode as the argument and assign a name to the new column - let's call it countryName.

You will see the following result:

How does it work in LINQ?

Use the operator select... as... and add the operation syntax to create the new column. This is the syntax of the ISO-3166-1 Country Name operation:

countryname(string)

Example

Note that you must have uploaded the following CSV file to your Devo domain as explained above to try out this example.

Copy the following LINQ script and try the above example on the my.upload.geolocation.data table.

from my.upload.geolocation.data
select split(message, ";", 5) as countryCode
select countryname(countryCode) as countryName