Modulo (mod, %%)

[ 1 Description ] [ 2 How does it work in the search window? ] [ 3 How does it work in LINQ? ]

Description

Adds a new column that returns the remainder of the division of the integer values in a field by another field or value.

Given the following example:

`rem(x, y)`

`rem(x, y)`

the Modulo operation calculates the remainder as follows, rounding down the result of the division (as can be done using the Floor (floor) operation):

`x - y * floor(x/y)`

`x - y * floor(x/y)`

The Division remainder (rem, %) operation also returns the remainder of a division, but instead rounds the result of the division to the nearest integer. Go to the operation article to learn more.

How does it work in the search window?

Select Create column in the search window toolbar, then select the Modulo operation. You need to specify two arguments:

Argument	Data type

Argument	Data type
Dividend ^mandatory	integer
Divisor ^mandatory	integer

The data type of the values in the new column is integer.

Example

In the my.upload.sample.data table, we want to find the remainder of the division of the values in the numbers_int field by 2.

The arguments needed to create the new field are:

Dividend - numbers_int field
Divisor - Click the pencil icon and enter 2

Click Create column and you will see the following result:

How does it work in LINQ?

Use the operator select... as... and add the operation syntax to create the new column. These are the valid formats of the Division remainder operation:

mod(integer1, integer2)
integer1 %% integer2

Example

You can copy the following LINQ scripts and try the above example on the my.upload.sample.data table.

from my.upload.sample.data
select split(message, ";", 17) as numbers,
int(numbers) as numbers_int,
numbers_int %% 2 as `numbers_int/2`

or

from my.upload.sample.data
select split(message, ";", 17) as numbers,
int(numbers) as numbers_int,
mod(numbers_int, 2) as `numbers_int/2`