Bitwise AND (band, &)

[ 1 Description ] [ 2 How does it work in LINQ? ] [ 3 How does it work in LINQ? ] [ 4 How does it work in the search window? ] [ 5 How does it work in LINQ? ]

Description

Creates a new field that retrieves the Bitwise AND of the specified arguments. Bitwise operations consider operands as bit patterns (zeros and ones) and work at the level of their individual bits.

The Bitwise AND operation compare bit by bit the equal-length binary representations of the selected pair of arguments. If both bits in the compared position are 1, the bit in the resulting binary representation is 1; otherwise, the result is 0. The result is then transformed and given in decimal format.

For example, if you add values 7 and 9 as arguments, the result is 0001, which is converted to its corresponding decimal value (1).

7 → 0111
9 → 1001

You can also use this operation on complex data types Set and Map to return the intersection between them. The behaviour of this operation changes depending on the data type it is executed on.

How does it work in the search window?

Select Create field in the search window toolbar, then select the Bitwise AND operation. You need to specify two arguments:

Argument	Data type

Argument	Data type
Number ^mandatory	integer
Number ^mandatory	integer

The data type of the values in the new field is integer.

Example

We want to get the Bitwise AND of the values in the posNumbers1_int and posNumbers2_int fields. We will create a new field using the Bitwise AND operation to do it. Let's call the new field bitAND.

The arguments needed to create the new field are:

Number - posNumbers1_int field
Number - posNumbers2_int field

Click Create field and you will see the following result:

How does it work in LINQ?

Use the operator select... as... and add the operation syntax to create the new field. These are the valid formats of the Bitwise AND operation:

band(integer1, integer2)
integer1 & integer2

Example

You can copy the following LINQ scripts and try the above example on the my.upload.sample.data table.

from my.upload.sample.data
select split(message, ";", 17) as posNumbers1
select split(message, ";", 18) as posNumbers2
select int(posNumbers1) as posNumbers1_int
select int(posNumbers2) as posNumbers2_int
  select band(posNumbers1_int, posNumbers2_int) as bitAND

or

from my.upload.sample.data
select split(message, ";", 17) as posNumbers1
select split(message, ";", 18) as posNumbers2
select int(posNumbers1) as posNumbers1_int
select int(posNumbers2) as posNumbers2_int
  select posNumbers1_int & posNumbers2_int as bitAND